Integrand size = 19, antiderivative size = 98 \[ \int \frac {1}{(a+b x)^{3/2} (c+d x)^{5/2}} \, dx=-\frac {2}{(b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {8 d \sqrt {a+b x}}{3 (b c-a d)^2 (c+d x)^{3/2}}-\frac {16 b d \sqrt {a+b x}}{3 (b c-a d)^3 \sqrt {c+d x}} \]
[Out]
Time = 0.02 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {47, 37} \[ \int \frac {1}{(a+b x)^{3/2} (c+d x)^{5/2}} \, dx=-\frac {16 b d \sqrt {a+b x}}{3 \sqrt {c+d x} (b c-a d)^3}-\frac {8 d \sqrt {a+b x}}{3 (c+d x)^{3/2} (b c-a d)^2}-\frac {2}{\sqrt {a+b x} (c+d x)^{3/2} (b c-a d)} \]
[In]
[Out]
Rule 37
Rule 47
Rubi steps \begin{align*} \text {integral}& = -\frac {2}{(b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {(4 d) \int \frac {1}{\sqrt {a+b x} (c+d x)^{5/2}} \, dx}{b c-a d} \\ & = -\frac {2}{(b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {8 d \sqrt {a+b x}}{3 (b c-a d)^2 (c+d x)^{3/2}}-\frac {(8 b d) \int \frac {1}{\sqrt {a+b x} (c+d x)^{3/2}} \, dx}{3 (b c-a d)^2} \\ & = -\frac {2}{(b c-a d) \sqrt {a+b x} (c+d x)^{3/2}}-\frac {8 d \sqrt {a+b x}}{3 (b c-a d)^2 (c+d x)^{3/2}}-\frac {16 b d \sqrt {a+b x}}{3 (b c-a d)^3 \sqrt {c+d x}} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.80 \[ \int \frac {1}{(a+b x)^{3/2} (c+d x)^{5/2}} \, dx=\frac {2 a^2 d^2-4 a b d (3 c+2 d x)-2 b^2 \left (3 c^2+12 c d x+8 d^2 x^2\right )}{3 (b c-a d)^3 \sqrt {a+b x} (c+d x)^{3/2}} \]
[In]
[Out]
Time = 0.58 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.97
method | result | size |
default | \(-\frac {2}{\left (-a d +b c \right ) \left (d x +c \right )^{\frac {3}{2}} \sqrt {b x +a}}-\frac {4 d \left (-\frac {2 \sqrt {b x +a}}{3 \left (a d -b c \right ) \left (d x +c \right )^{\frac {3}{2}}}+\frac {4 b \sqrt {b x +a}}{3 \left (a d -b c \right )^{2} \sqrt {d x +c}}\right )}{-a d +b c}\) | \(95\) |
gosper | \(-\frac {2 \left (-8 d^{2} x^{2} b^{2}-4 x a b \,d^{2}-12 x \,b^{2} c d +a^{2} d^{2}-6 a b c d -3 b^{2} c^{2}\right )}{3 \sqrt {b x +a}\, \left (d x +c \right )^{\frac {3}{2}} \left (a^{3} d^{3}-3 a^{2} b c \,d^{2}+3 a \,b^{2} c^{2} d -b^{3} c^{3}\right )}\) | \(104\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 273 vs. \(2 (82) = 164\).
Time = 0.43 (sec) , antiderivative size = 273, normalized size of antiderivative = 2.79 \[ \int \frac {1}{(a+b x)^{3/2} (c+d x)^{5/2}} \, dx=-\frac {2 \, {\left (8 \, b^{2} d^{2} x^{2} + 3 \, b^{2} c^{2} + 6 \, a b c d - a^{2} d^{2} + 4 \, {\left (3 \, b^{2} c d + a b d^{2}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{3 \, {\left (a b^{3} c^{5} - 3 \, a^{2} b^{2} c^{4} d + 3 \, a^{3} b c^{3} d^{2} - a^{4} c^{2} d^{3} + {\left (b^{4} c^{3} d^{2} - 3 \, a b^{3} c^{2} d^{3} + 3 \, a^{2} b^{2} c d^{4} - a^{3} b d^{5}\right )} x^{3} + {\left (2 \, b^{4} c^{4} d - 5 \, a b^{3} c^{3} d^{2} + 3 \, a^{2} b^{2} c^{2} d^{3} + a^{3} b c d^{4} - a^{4} d^{5}\right )} x^{2} + {\left (b^{4} c^{5} - a b^{3} c^{4} d - 3 \, a^{2} b^{2} c^{3} d^{2} + 5 \, a^{3} b c^{2} d^{3} - 2 \, a^{4} c d^{4}\right )} x\right )}} \]
[In]
[Out]
\[ \int \frac {1}{(a+b x)^{3/2} (c+d x)^{5/2}} \, dx=\int \frac {1}{\left (a + b x\right )^{\frac {3}{2}} \left (c + d x\right )^{\frac {5}{2}}}\, dx \]
[In]
[Out]
Exception generated. \[ \int \frac {1}{(a+b x)^{3/2} (c+d x)^{5/2}} \, dx=\text {Exception raised: ValueError} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 373 vs. \(2 (82) = 164\).
Time = 0.34 (sec) , antiderivative size = 373, normalized size of antiderivative = 3.81 \[ \int \frac {1}{(a+b x)^{3/2} (c+d x)^{5/2}} \, dx=-\frac {4 \, \sqrt {b d} b^{3}}{{\left (b^{2} c^{2} {\left | b \right |} - 2 \, a b c d {\left | b \right |} + a^{2} d^{2} {\left | b \right |}\right )} {\left (b^{2} c - a b d - {\left (\sqrt {b d} \sqrt {b x + a} - \sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d}\right )}^{2}\right )}} - \frac {2 \, \sqrt {b x + a} {\left (\frac {5 \, {\left (b^{6} c^{2} d^{3} {\left | b \right |} - 2 \, a b^{5} c d^{4} {\left | b \right |} + a^{2} b^{4} d^{5} {\left | b \right |}\right )} {\left (b x + a\right )}}{b^{7} c^{5} d - 5 \, a b^{6} c^{4} d^{2} + 10 \, a^{2} b^{5} c^{3} d^{3} - 10 \, a^{3} b^{4} c^{2} d^{4} + 5 \, a^{4} b^{3} c d^{5} - a^{5} b^{2} d^{6}} + \frac {6 \, {\left (b^{7} c^{3} d^{2} {\left | b \right |} - 3 \, a b^{6} c^{2} d^{3} {\left | b \right |} + 3 \, a^{2} b^{5} c d^{4} {\left | b \right |} - a^{3} b^{4} d^{5} {\left | b \right |}\right )}}{b^{7} c^{5} d - 5 \, a b^{6} c^{4} d^{2} + 10 \, a^{2} b^{5} c^{3} d^{3} - 10 \, a^{3} b^{4} c^{2} d^{4} + 5 \, a^{4} b^{3} c d^{5} - a^{5} b^{2} d^{6}}\right )}}{3 \, {\left (b^{2} c + {\left (b x + a\right )} b d - a b d\right )}^{\frac {3}{2}}} \]
[In]
[Out]
Time = 1.77 (sec) , antiderivative size = 132, normalized size of antiderivative = 1.35 \[ \int \frac {1}{(a+b x)^{3/2} (c+d x)^{5/2}} \, dx=\frac {\sqrt {c+d\,x}\,\left (\frac {16\,b^2\,x^2}{3\,{\left (a\,d-b\,c\right )}^3}+\frac {-2\,a^2\,d^2+12\,a\,b\,c\,d+6\,b^2\,c^2}{3\,d^2\,{\left (a\,d-b\,c\right )}^3}+\frac {8\,b\,x\,\left (a\,d+3\,b\,c\right )}{3\,d\,{\left (a\,d-b\,c\right )}^3}\right )}{x^2\,\sqrt {a+b\,x}+\frac {c^2\,\sqrt {a+b\,x}}{d^2}+\frac {2\,c\,x\,\sqrt {a+b\,x}}{d}} \]
[In]
[Out]